func main(){
type ColorGroup struct {
ID int
Name string
Colors []string
}
group := ColorGroup{
ID: 1,
Name: "Reds",
Colors: []string{"Crimson", "Red", "Ruby", "Maroon"},
}
//
b, err := json.Marshal(&group)
//
b, err := json.Marshal(group)
if err != nil {
fmt.Println("error:", err)
}
os.Stdout.Write(b)
}
/ / the first way
b, err := json.Marshal(&group)/ / the second way
b, err := json.Marshal(group)
the running results are: {"ID": 1, "Name": "Reds", "Colors": ["Crimson", "Red", "Ruby", "Maroon"]}
the b result is the same in both ways. Go is the value transfer, the first is to pass a copy of the pointer, and the second is to pass a copy of the structure.
so I think the question is how does the Marshall function mask the details of different parameters?
Why can both pass pointers and structures achieve the same effect?
the foundation of go is not good. Thank you for your advice.