File name problem of Node-sass parameter instruction

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I want to compile and output all the .scss files in the scss directory to the css directory of dist

I wrote the parameter: npm run node-sass. / scss/ .scss. / dist/css/ .css

The

structure is not as I expected. All the scss files in the source directory can be recognized, but there are multiple * .css instead of the same name after compilation. Can you tell me how to do this?

Html5 css sass node.js

Jun.28,2021

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