Table structure: create table test_tmp (
 id int, 
 log_time datetime, 
 item varchar (10) 
) 
 create table test_d (
 id int, 
 name varchar (10) 
) 
 Test data: 
 insert into test_d values (1, "hh"); 
 insert into test_d values (2," xx"); 
 insert into test_tmp values (1, "2018-08-16 16 hh" 13 hh" 36 cycles," a"); 
 insert into test_tmp values (1, "2018-08-16 16 13 hh" 36 cycles," b"); 
 insert into test_tmp values (1, "2017-08-16 16 13 hh" 36 cycles," a"); 
 insert into test_tmp values (1, "2017-08-16 16 br 1336," b"); 
 insert into test_tmp values (1, "2018-08-16 16 13 br 36," a"); 
 insert into test_tmp values (2, "2018-08-16 16 br 1336," a"); 
 insert into test_tmp values (2, "2018-08-16 16 br 1336," b"); 
 insert into test_tmp values (2, "2017-08-16 16 br 1336," a"); 
 insert into test_tmp values (2, "2017-08-16 16 13 br 36," b"); 
 insert into test_tmp values (2, "2017-08-16 16 13 13 36," c"); 
 I can only get all of what I write now. How can I get the item (separated by commas) of the most recent record (time) of each id? 
 select * from test_d d left join (select id, log_time, group_concat (item) from test_tmp group by id, log_time) t on d.id = t.id 
  
