because you don"t want to manually go to xftp and pull the packaged code into the project directory after each package, gulp and gulp-sftp are used to upload the code as follows:

  var gulp = require("gulp")
  var sftp = require("gulp-sftp")
  gulp.tast("default", function () {
    return gulp.src("/dist/**/*")
      .prpe(sftp({
        host: "xxxxx",
        port: 22,
        user: "xxxxx",
        pass: "xxxxx",
        remotePath: "xxxxx"
      }))
  })

upload is no problem, but will not delete the existing code package, I would like to ask, how to delete the existing code? I probably understand that it is operated through the command of ftp, but I don"t have any clue about it. Please advise ~