Object obj=new Object();
Object obj2=obj;
synchronized(obj){}
synchronized(obj2){}what if this is the case?
Object obj=new Object();
synchronized(obj){}
obj=new Object();
synchronized(obj){}
Object obj=new Object();
Object obj2=obj;
synchronized(obj){}
synchronized(obj2){}what if this is the case?
Object obj=new Object();
synchronized(obj){}
obj=new Object();
synchronized(obj){} the above two synchronized blocks are mutually exclusive.
so based on the fact that this lock object may be misused, it is recommended to use a separate final object as the lock instead of the business-related variable:
:synchronized(obj){}objobjobjsynchronized(obj){}
:
static Object obj=new String("a");
public static void main(String[] args) throws InterruptedException {
class a extends Thread{
@Override
public void run() {
synchronized(obj){
for (int i = 0; i < 10000; iPP) {
if(i%10==0)System.out.println(obj+",0");
}
}
}
}
new a().start();
Thread.sleep(10);
obj=new String("b");
class b extends Thread{
@Override
public void run() {
synchronized(obj){
for (int i = 0; i < 10000; iPP) {
if(i%10==0)System.out.println(obj+",1");
}
}
}
}
new b().start();
}
Test results: if the output of two threads is crossed, Synchronize will indeed fail
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