How do two Obj-array Filter drop the same item?

    var arr = [
        {
            id: 111,
            name: "aaa"
        },
        {
            id: 222,
            name: "bbb"
        },
        {
            id: 333,
            name: "ccc"
        }
    ]

    var arr1 = [
        {
            id: 111,
            name: "aaa"
        },
        {
            id: 222,
            name: "bbb"
        }
    ]

    
    //
    var arr2 = [{
        id: 333,
        name :"ccc"
    }]
Javascript
Mar.03,2021

should we consider that the same id is the same? Or is it an overall comparison? Of course, this thing is called key anyway, so let's assume id comparison.

introduce lodashjs , 

console.log(_.xorBy(arr1, arr, 'id'), "id")

if it is other key, such as overall comparison. So 

console.log(_.xorBy(arr1, arr, function(v){return JSON.stringify(v)}),'fun')

you can do this if there are no duplicate objects in an array, although it doesn't feel very efficient 

var copyArr = arr2.map(val => JSON.stringify(val))

arr1 = arr1.filter(obj => {
  let index = copyArr.indexOf(JSON.stringify(obj))
  
  if (index === -1) return true
  arr2.splice(index, 1)
  copyArr.splice(index, 1)

})

arr1.concat(arr2)

let intersection = arr1.filter (v = > arr2.includes (v))
arrays take intersection

you can try this:

take the complement of arr1 concat arr2 , that is, the non-intersection of the two. The rules after
is used to implement reusable functions. Just pass in the key collection to check. 



  function filter (arr1, arr2, rules) {
    return arr1.filter(item1 => !arr2.some(item2 => rules.every(key => item1[key] === item2[key])))
  }

  function build (arr1, arr2, rules) {
    return [].concat(filter(arr1, arr2, rules), filter(arr2, arr1, rules))
  }

  let result = build(arr1, arr2, ['id', 'name'])

  console.log(result)

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