Is this the arrow function?

function delay(n) {
  return new Promise(resolve => setTimeout(resolve, n))
}

the return statement in this function is a little difficult to understand. 

resolve => setTimeout(resolve, n)

= > is this an arrow function?
if yes, resolve is the parameter of setTimeout,

The

delay function takes an argument n, and this setTimeout function introduces a new parameter.

it"s a little confusing. Please explain.

Javascript
Mar.12,2021

https://developer.mozilla.org.
suggests viewing Promise documents

the complete state is as follows: let delay = n = > new Promise (resolve = > setTimeout (resolve,n));
promise ) is the first parameter of the callback function resolve is to change the state to success
setTimeout the first argument is the callback function's second parameter is the delay time setTimeout (resolve,n) is n millisecond later call resolve < / 

function delay(time) {
  return new Promise(function(resolve){
    setTimeout(resolve, time)
  })
}

delay(3000) //3promise

there is a setTimeout in the arrow function

Previous: Now there is a web web page. If you want to adapt to the mobile terminal, please give me some ideas.

Next: Can Mini Program imitate live rolling comments?

css mysql arrays josn react html typescript webpack npm sass R objective-c .net sql-server jquery python-3.x angularjs django angular excel regex iphone ajax linux xml pandas vba spring database wordpress string wpf xcode windows bash postgresql oracle multithreading eclipse list firebase algorithm macos forms image scala visual-studio azure bootstrap spring-boot react-native python-2.7 docker performance function winforms matlab powershell apache dataframe api sqlite numpy rest shell selenium flutter dart maven loops qt swing android-studio csv express file class tensorflow sorting codeigniter perl
© 2021 CodesHelper
Advertising Contact us About us
Menu