looking at some blogs on the Internet, it is said that if using invokeAll is equivalent to dividing A to B, both An and B will finish the work.
where can I see the source code of https://blog.csdn.net/cxl0921.
https://www.liaoxuefeng.com/d.
invokeAll?
take public static void invokeAll (ForkJoinTask T1, ForkJoinTask T2) as an example.
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