let a =[1,2,3,4,5]; let b = [[1,2],[3,4],5] how to quickly implement the above a-> b operation? ...
$product_name = $pdo->query( "SELECT * FROM `stock` as s JOIN `product` as p ON p.prod_id = s.prod_id WHERE s.order_id = {$first_order[ order_id ]} " ); $productNameArray = null; while ($row = mysqli...
assign a to b let a = [{ m: 1 }] let b = [...a] b[0].m = 2 console.log(a) console.log(b) result: [{m: 2}] a [{m: 2}] b when you change the attribute of an element in b, the m attribute in the corresponding element of an also changes ...
there is a usr table containing uid,username business table 1, the information stored are fields uid,username business table 2, and only uid, (multiple data in business table 2 corresponds to one data in business table 1) the environmental backgrou...
can you upload pictures by curl simulating the following html form $file_obj = curl_file_create(realpath($file), image png ); $data[ imgs ][] = $file_obj; that is to say, this is the kind of thing. But this will report an error, Array to str...
$arr = [1,2,3]; var_dump($arr); syntax error, unexpected [ ; tp;...
such as question: how to set chunksize and shape? of dask.array the code is as follows >>> x = data.values >>> x dask.array<values, shape=(nan, 24), dtype=int64, chunksize=(nan, 24)> >>> y = data[ label ].values >...
there are now two arrays String arg1 [] = { "a ", "b ", "c "}; String arg2 [] = { "01 ", "02 "}; in addition to using two for loops, what is the other way to combine two arrays into {a01Magi a02dir b01Magi c02MagneC02} I would like to ask...
because every user will have one or more attribute structures like this: so if I do this <? foreach ($data->{ attributes } as $value) { echo $value; }?> can list every id now the problem is that this array has several different c...
such as when querying BTC. Take out the BTC data inside. when querying ETH. Just withdraw all the data in the ETH. { "data": { "1": { "id": 1, "name": "Bitcoin", ...
is the simplest math problem: finding the set, intersection and union of two arrays. I know you can use for loops, but is there an easier way? var arr1 = [3, 5, 1]; var arr2 = [2, 5, 7]; ...... ...
PageTagMapModel.getPageTagMapNum ({tag: single._id, status: normal }) returns the page_num found by the mongoose query, but if three lines of comments are used in the code, there is no page_num attribute in the resulting data. You can use = to assig...
<!doctype html> <html> <head> <meta charset="utf-8"> <title>< title> <meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1, user-scalable=no"> < head&...
The main function receives the array processed by the subfunction, and an exception occurs when traversing the array sample code: -sharpinclude<stdio.h> -sharpinclude<stdlib.h> -sharpinclude<string.h> void demo(char *list[]) { ...
this problem has been bothering me not to be able to Rest for several days! How to reassemble it into a new format? the content is written at will. Mainly the format! The number after sitePerEpisode is the number of sets : $ceshi= $$1$http: v.you...
function makeRow(v=0){ const array = new Array(3); array.fill(v); return array; } function makeMatrix(v = 0){ const array = new Array(3) array.fill(makeRow(v)) ...
$arr=array("a","b","c","d"); foreach ($arr as &$value) { } $value=&arr[3];$value="d"; foreach ($arr as $key=>$value) { echo ""; var_dump($arr); } the results are as follow...
has the following format { "2": { "id": 2, "name": "demo1", "lv1": { "4": { "id": 20, "name": "...
public void print(Object, String ... args){ for(int i = 0 ; i < args.length; iPP){ println(args[i]); } } now there is an array String [] p1 = { "Xiaoming ", "Xiao Hong ", "Xiaohua "} String [] p2 = { "Xiaomi ", "Samsung "...
there are two arrays arr01 and arr02 now add a field from the arr01 array to the arr02. The problem now is that the resulting new array is always the last field of the arr01 let arr01 = [ { "account" : "000000000000" ...
I execute the command: git diff sub_a master > > diff2.diff see a lot of differences I now see that some submission records of master are not merged into sub_a, so I use the above command to compare the next two branches. I display Already up-to-da...
The replace of js can only be replaced by the first one. How do you replace all of them? the way of RegExp is similar to "( " is there a mistake? is there a more elegant way to write it? String.prototype.replaceAll = function (FindText, RepText) { ...
there is a piece of code in the front-end js that doesn t know what language or framework to write, and the background is php. Which great god knows < script id= "aa " type= "text html " > {if (list.iRet!= 0 )} <tr> ...
after the project is opened in ipad, it is found that the effective position of the click button is different from the display position. ~ for example, when you click the login button, you have to click about the location above to trigger the login eve...
recently read the front-end https: www.w3cplus.com mobil. this article, feel very troublesome, why not learn Android ...